[Radiance-general] Reflection vs specularity

[atelier iebele abel]

Hi Carsten,

Thanks for pointing out  the right direction again.
I replaced the line with:

refl = (1-multi)^9 ;

Works fine now, just a few days before my holidays :)
Now I  have it , it looks so simple, and the my question almost stupid.
Thanks!

Iebele


>> refl  =  
>> (1-multi)*(1-multi)*(1-multi)*(1-multi)*(1-multi)*(1-multi)*(1-multi)*(1-multi)*(1-multi) 
>> ;
>>
> The functional language defines a pure exponential funtion e^x ( or 
> exp(x), as it is called). To calculate arbitray powers with it, 
> proceed as follows:
>  x^y   = e^y*lnx  or  x^y = exp(y*log(x))  in the syntax of the 
> functional language
>
> -cb
>
> _______________________________________________
> Radiance-general mailing list
> Radiance-general at radiance-online.org
> http://www.radiance-online.org/mailman/listinfo/radiance-general
>
>