[Radiance-general] Remove attenuation and specify ray distance of an IES light source?
Greg Ward
gregoryjward at gmail.com
Sun Jul 16 17:11:26 PDT 2017
Hi John,
If I understand your query, you just want to "see" what is within a certain distance from a point -- it that right?
To generate an image from the light source's perspective to some maximum distance, just use an rpict or rvu view with a fisheye view and aft clipping distance:
-vta -vp Lx Ly Lz -vh 360 -vv 360 -va Dmax
Where (Lx,Ly,Lz) is the position of your light source (or just in front of it) and Dmax is how far you want to look. You may also need the -vd and -vu specs to specify the central view direction and distance. The above will generate a 360° fisheye view, which may be larger than you want, so adjust accordingly.
If instead you want to illuminate your scene, but only for points within some distance of a source, you can use the "glow" type:
void glow limited_light
0
0
4 1000 1000 1000 Dmax
limited_light sphere limited_bulb
0
0
5 Lx Ly Lz 1
Again, you'll need to insert the appropriate values for your source position, and this light will still have a 1/r^2 fall-off. Also, make sure to set "-ab 0" in your rendering, so it doesn't try to count the glow source in the indirect calculation.
If you want to eliminate the fall-off, you can use a compensating pattern like so:
void brightfunc square_riseup
2 T*T .
0
0
square_riseup glow limited_light
0
0
4 1 1 1 Dmax
limited_light sphere limited_bulb
0
0
5 Lx Ly Lz 1
This will still have a cosine-orientation effect on your surfaces, but no fall-off.
Hope this helps.
-Greg
> From: John Everist <john.everist at icloud.com>
> Date: July 16, 2017 4:22:51 PM PDT
>
> Hello community,
>
> Is it possible to totally break the laws of physics in radiance? Can I make a calculation with an IES file where I can terminate the ray distance (at 100 metres for example) and remove any attenuation from the rays?
>
> In summary, i want to use radiance to identify 'line of sight' to a maximum distance - a point was/was not 'seen' from the light source position.
>
> Its properly an easy question but i cant find the answer. I have the rendering with radiance book if e answer is in there...
>
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