[Radiance-general] rtcontrib

[Jia Hu]

Thank you! I have other questions related to this program.

(1) Question 1:

In the case that both of "-f", "-b" and "-m" are used, the .cal algorithm
and "-b" option are applied to objects with "-m" materials, for example,

vwrays -ff $vw |rtcontrib @image.opt -ffc $(vwrays -d $vw) -f tregenza.cal
-b tbin -o images/patches/p%03d%s.hdr \
-m sky_glow -m ground_glow -w testroom_whitesky.oct

If I replace "ground_glow" with "ceiling_mat", the .cal will applied to
"ceiling" geometry and divide ceiling into many patches according to the ray
direction and intersection with ceiling?

(2) Question 2:

Assume my model has two windows in the south wall and one sensor in the
interior building, and I wish to calculate the daylighting coefficient of
each patch of sky and each window to the illuminance at the sensor point.
The result is like a matrix as follows:

                    SkyPatch001,       SkyPatch001,
Window01     coefficient (RGB)   coefficient (RGB)
Window02     coefficient (RGB)   coefficient (RGB)

Each coefficient shows the contribution of each sky patch and each window to
the sensor illuminance. Can I achieve this in one rtcontrib command?
Is the following expression right?

[input ray] | rtcontrib -f tregenza.cal -o window_%s.data -b tbin -m
window01_mat -b -b tbin -m window02_mat  [other necessary options]

Thank you,

Jia

On Wed, Jul 13, 2011 at 7:05 PM, Greg Ward <gregoryjward at gmail.com> wrote:

> "Yes" is the short answer.  Using the rtcontrib -V+ option, you will get
> the contribution from each surface or set of surfaces selected by -m.
>
> Best,
> -Greg
>
> > From: Jia Hu <hujia06 at gmail.com>
> > Date: July 13, 2011 2:22:41 PM PDT
> >
> > Hello experts:
> >
> > If using -m option in rtcontrib, can I calculate the contribution from a
> general object that does not belong to light source, such as objects having
> plastic materials?
> >
> > My model has two windows, and I want to calculate the contribution of
> each window to the illuminance at sensor points. The "Three-Phase Daylight
> Coefficient" method works. But for simple windows, can I directly calculate
> the contribution using rtcontrib or others?   Any suggestion is greatly
> appreciated.
> >
> > Thank you!
> >
> > Jia
>
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