[Radiance-general] experiences with the photon map
Lars O. Grobe
akilog at nus.edu.sg
Fri Jan 2 02:16:32 PST 2009
> I think you are right. Anyhow, I'm not sure, if Roland implemented the
> correct pmap conform rpict-call within findglare - I'm pretty sure he
> never worked on that. Therefore there is no other way as rendering the
> whole hemisphere and than evaluating the picture.
Help!!! I do not get it... to get the illuminance from a 180 degree
fisheye picture (no matter if taken by a camera or rendered by rpict), I
have to integrate the luminance values over the circular surface of the
projected hemisphere. This means that I somehow have to sum-up the pixel
values. Still I do not really know the maths to do it, can anyone give
me a hint, please? Is it the average of the pixel values multiplied by
the surface area, the pixel values being weighted according to the
solid angles they cover?
CU Lars.
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